18x^2=17

Solution for 18x^2=17 equation:

18x^2=17

We move all terms to the left:

18x^2-(17)=0

a = 18; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·18·(-17)
Δ = 1224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1224}=\sqrt{36*34}=\sqrt{36}*\sqrt{34}=6\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{34}}{2*18}=\frac{0-6\sqrt{34}}{36}
=-\frac{6\sqrt{34}}{36}
=-\frac{\sqrt{34}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{34}}{2*18}=\frac{0+6\sqrt{34}}{36}
=\frac{6\sqrt{34}}{36}
=\frac{\sqrt{34}}{6}
$